What are the sample 2nd mid-semester question papers and answers for 6th-grade Mathematics in Vietnam? What are the requirements regarding the content of 6th-grade Mathematics textbooks in Vietnam?

What are the sample 2nd mid-semester question papers and answers for 6th-grade Mathematics in Vietnam?

Students can refer to the following sample 2nd mid-semester question papers and answers for 6th-grade Mathematics in Vietnam:

Sample 2nd mid-semester question papers and answers for 6th-grade Mathematics in Vietnam

Question paper No. 1:

A: Multiple Choice

Question 1: Among the following writings, which one gives us a fraction?

A. 30	B. 0,253	C. 47	D. 1,252,7

Question 2: Two fractions ab and cd (where a, b, c, d are non-zero integers) are equal if:

Question 3: Which of the following fractions is equal to −3/5?

A. −915	B. 515	C. −310	D. −105

Question 4: Given two points A and B on ray Ot with OA = 4cm, OB = 8cm, then:

A. A is the midpoint of segment OB

B. O is the midpoint of segment AB

C. B is the midpoint of segment OA

D. No segment has a midpoint

Question 5: The result of the calculation (-4.44 + 60 - 5.56) : (1.2 - 0.8) is:

Question 6: Which of the following integers m satisfies m8>−78?

Question 7: Calculate the area of a square with a side length of 12.3m (Round to the nearest tens)

Question 8: Class 6A has 40 students, with 12.5% being excellent students. The number of excellent students in class 6A is:

Question 9: Given ray Mx, let point O be on ray Mx. Draw ray MN so that it is the opposite of ray Mx. Which of the following statements is true?

A. Ray MN also passes through point O

B. Points M and N are on the same side relative to point O

C. Point O is between points M and N

D. Point N does not belong to line MO

Question 10: In a box, there are some blue pens, some yellow pens, and some red pens. Randomly pick one pen, check its color, and return it. Repeat this activity 40 times and obtain the following results:

Calculate the experimental probability of drawing a red pen

B. Essay Section

Question 1: Perform the calculations:

2. Find x:

b, x + 3.25 = 6.15

Problem 3: A construction contractor agrees to build a house at a cost of 360,000,000 VND but the homeowner asks to reduce the cost by 2.5% and the contractor agrees. Calculate the amount of money the contractor receives for building the house.

Problem 4: On ray Ox, take two points A and B such that OA = 3 cm; OB = 6 cm.

a) Is point A between points O and B? Why?

b) Compare OA and AB.

c) Prove that point A is the midpoint of OB.

d) Take point C on ray Ox such that C is the midpoint of segment AB. Calculate the length of segment OC.

Problem 5: Calculate the sum:

Answers

I. Answers to the Multiple Choice Section

II. Answers to the Essay Section

Question 1:

a) (716+−18+932):54=1932:54=1932.45=1940

b) 1029+235−629=(1029−629)+235=4+135=335

c) 30%−225+0,2.12=310−125+210.12=15−125=−115

d) −2530.3744+−2530.1344+−2530.−644

=−2530.(3744+1344+−644)=−2530.4444=−2530

2. Find x:

a) 2.5x+47=−1.5

So x = -29/35

b) x + 3.25 = 6.15

x = 6.15 – 3.25

x = 2.9.

Therefore, x = 2.9.

Problem 3 (1.5 points):

Method 1:

If the initial amount the contractor receives for building the house is considered 100%, the amount after the reduction is:

100% − 2.5% = 97.5%

The amount the contractor receives for building the house is:

360,000,000 × 97.5 / 100 = 351,000,000 VND

Therefore, the amount the contractor receives for building the house is 351,000,000 VND.

Method 2:

The amount reduced by the homeowner is:

360,000,000 × 2.5 / 100 = 9,000,000 VND

The amount the contractor receives for building the house is:

360,000,000 – 9,000,000 = 351,000,000 VND

Therefore, the amount the contractor receives for building the house is 351,000,000 VND.

Problem 4 (2.5 points):

a) On ray Ox, we have OA < OB (since 2 cm < 4 cm)

Therefore, point A is between two points O and B.

b) Since point A is between two points O and B:

OA + AB = OB

3 + AB = 6

Hence, AB = 6 – 3 = 3 (cm).

And OA = 3 cm.

So OA = AB.

c) Point A is the midpoint of segment OB because:

+ Point A is between two points O and B (proved in part a)

+ OA = AB (proved in part b)

Therefore, point A is the midpoint of segment OB.

d) Since point C is the midpoint of segment AB:

Point C is between points O and B because:

+ Points O, B, C all lie on a straight line (same ray Ox)

+ BC < OB (1.5 cm < 6 cm)

Since point C is between points O and B:

OC + BC = OB

OC + 1.5 = 6

Therefore, OC = 6 – 1.5 = 4.5 (cm).

Therefore, OC = 4.5 cm.

Problem 5 (0.5 points):

Question paper No. 2

I. MULTIPLE CHOICE SECTION: (2 points) Circle the letter that precedes the correct answer

Question 1: Among two fractions with the same positive denominator, the fraction with the larger numerator is

A. larger

B. smaller

C. cannot be compared

D. equal

Question 2: Knowing 52x=4. The value of x is

A. 10

B. 85

C. 58

D. 15

Question 3: The value of y so that 37=−24y is

A. y = 49

B. y = −56

C. y = 56

D. y = −49

Question 4: Observe the figure and say which statement is correct

A. Point A belongs to line d

B. Point C belongs to line d

C. Line AB passes through point C

D. Points ABC are collinear

Question 5: The value mn of a is

A. mn:a

B. a:mn

C. mn⋅a

D. nm⋅a

Question 6: Assigned by the teacher to compile the midterm math test scores for members of the group, Minh compiled the following table:

Based on the above statistics, the number of students who scored 8 is

A. 8 students

B. 4 students

C. 1 student

D. 3 students

Question 7: The bar chart below shows the number of tourists (unit: people) visiting certain localities in 2018.

According to the bar chart above, which locality has the most tourists visiting and what is the number?

A. Nha Trang with 45,000 people

B. Da Nang with 60,000 people

C. Da Nang with 50,000 people

D. Hue with 36,000 people

Question 8: Given segment AB = 6cm. M is a point on segment AB such that MB = 5cm. Then the length of segment MA is

A. 1 cm

B. 3 cm

C. 11 cm

D. 2 cm

II. ESSAY SECTION: (8 points)

Question 1 (2 points). Perform the calculations (calculate reasonably if possible):

a) 35+−49

b) 35+25⋅158

c) 72⋅813+813⋅−52+813

d) −517⋅−923+923⋅−2217+11923

Question 2 (2 points). Find x:

a) 78+x=35

b) 13:(2x−1)=−424

c) 172−|x−34|=−74

d) (3x+2)(−25x−7)=0

Question 3 (1 point)

Mr. Ba wants to lay down bricks and plant grass in the garden. The area for planting grass is 1/5 the area of the garden, and the area for tiled floor is 36m^2^

a) Calculate the area of the garden.

b) The price of 1m^2^ of grass is 50,000 VND, but Mr. Ba gets a 5% discount. How much does he need to pay for the grass?

Question 4 (2 points)

On ray Ox, choose two points A and B such that: OA = 3cm, OB = 6cm.

a) Name the rays overlapping at point O and the opposite rays at point A.

b) Is point A the midpoint of segment OB? Why?

Question 5 (1 point)

a) Calculate the sum: M=1+15+335+…+39603+39999

b) Prove that:

S=142+162+182+…+1(2n)2<14(n∈N,n≥2)

Answers

Part I: Multiple Choice (2 points).

Each correct answer earns 0.25 points.

Part II: Essay (8 points)

What are the sample 2nd mid-semester question papers and answers for 6th-grade Mathematics in Vietnam? What are the requirements regarding the content of 6th-grade Mathematics textbooks in Vietnam? (Image from Internet)

What are the requirements regarding the content of 6th-grade Mathematics textbooks in Vietnam?

According to Article 5 of the Regulation issued with Circular 33/2017/TT-BGDDT, the requirements regarding the content of 6th-grade Mathematics textbooks in Vietnam include:

- The contents of textbooks must present accurately and adequately the contents of the subject’s program or the educational activity; ensure the basic, scientific and practical characteristics and be consistent with the reality of Vietnam.

- The terms, concepts, definitions, figures, events, images used in textbooks shall be accurate, objective, consistent and suitable for students’ ages; the cited figures, events, images shall have clear sources.

- New scientific achievements relating to the subject's program, educational activities shall be updated on the textbook to meet the requirements of international integration and the objectives of the subject’s program and educational activity.

- The contents of national sovereignty, human rights, children’s rights, gender equality, sustainable development, environment protection, adaptation to climate change shall be presented properly.

What is the process of selecting 6th-grade Mathematics textbooks in Vietnam?

Under Article 7 of Circular 27/2023/TT-BGDDT, the process of selecting 6th-grade Mathematics textbooks in Vietnam is as follows:

Step 1: The council prepares a plan to organize the selection of textbooks for the educational institution, assigning tasks to council members.

Step 2: Organize the selection of textbooks at the professional team

- Based on the council's plan and textbook selection criteria, the head of the professional team develops a plan to organize the selection of textbooks for each subject structured in the professional team, reporting to the head before implementation;

- Organize for all subject teachers at the educational institution (including permanent, contract, seconded, adjunct, and inter-school teachers) to participate in selecting the textbooks for that subject;

- At least 20 days before the first meeting of the professional team, the head of the professional team organizes for subject teachers to study the textbooks and write assessments on the textbooks based on selection criteria;

- The head of the professional team organizes a meeting with subject teachers to discuss, vote, and select one textbook for the subject. If a subject only has one textbook approved by the Minister of Education and Training, the professional team selects that textbook without voting.

A textbook is selected if it obtains votes from at least half of the subject teachers.

If no textbook obtains votes from at least half of the subject teachers, the professional team must discuss and vote again; the selected textbook is the one that has the most teacher votes in the second round.

In both voting rounds, if there are two or more textbooks with the highest equal number of teacher votes, the head of the professional team decides which textbook to select.

Meetings of the professional team are documented, recording all comments and assessments of the textbooks by participating subject teachers, with the minutes signed by the head of the professional team and the assigned minutes taker;

- The head of the professional team summarizes the results and compiles the list of textbooks selected by the professional team, with signatures by the head of the professional team and the assigned compiler.

Step 3: The council meets to discuss and assess the organization of textbook selection by professional teams; verifies the meeting minutes of the professional team; teacher's assessments on textbooks as prescribed in Clause 2, Article 7, Circular 27/2023/TT-BGDDT; compiles the results of textbook selection by professional teams into minutes (including comments and assessments on the organization of textbook selection by professional teams; the list of textbooks selected by professional teams), with signatures by the Chairman and Secretary of the Council.

Step 4: The council proposes to the head the list of textbooks selected by professional teams according to the regulations of Circular 27/2023/TT-BGDDT.

Step 5: The educational institution compiles a portfolio of selected textbooks and sends it to the Division of Education and Training (for primary and lower secondary education) or the Department of Education and Training (for upper secondary education)